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4x^2+24.7x+19=0
a = 4; b = 24.7; c = +19;
Δ = b2-4ac
Δ = 24.72-4·4·19
Δ = 306.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24.7)-\sqrt{306.09}}{2*4}=\frac{-24.7-\sqrt{306.09}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24.7)+\sqrt{306.09}}{2*4}=\frac{-24.7+\sqrt{306.09}}{8} $
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